Question

simplify : ( a+b+c ) ( a-b+c )​

Answer 1

Answer:

$(a+b+c)(a-b+c)\\\\=[(a+c)+b][(a+c)-b]$

now if we take a + c = y & b = x

Thus ,

$[x +y][x-y]$

using the identity $(x+y)(x-y)=x^{2}-y^{2}$

putting the values of x & y

$(a+c)^{2}-(b)^{2}\\\\(a^{2}+c^{2}+2ac)-b^{2}\\\\=a^{2}+c^{2}-b^{2}+2ac$

Answer 2

Answer:

=a^2+c^2+2ac-b^2

Step-by-step explanation:

take a+c inside a bracket .

{(a+c)+b}{(a+c)-b}

now using identity (x+y)(x-y)=x^2-y^2

let a+c be x and b be y

so , x2-y2

=(a+c)^2 - b^2

=a^2+c^2+2ac-b^2