simplify (a+b+c) (a+b-c)
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Answered by
0
a²+b²-c²+2ab
Step-by-step explanation:
\begin{gathered}(a+b+c)(a+b-c)\\\\= a^2 + ab - ac + ab + b^2 - bc + ac + bc - c^2\\\\= a^2 + b^2 + c^2 + ab + ab -ac + ac - bc + bc\\\\= \boxed{a^2 + b^2 - c^2 + 2ab}\end{gathered}
(a+b+c)(a+b−c)
=a
2
+ab−ac+ab+b
2
−bc+ac+bc−c
2
=a
2
+b
2
+c
2
+ab+ab−ac+ac−bc+bc
=
a
2
+b
2
−c
2
+2ab
Answered by
0
Answer:
Hello! The answer to this is :-
(a+b+c)(a+b-c)
=a(a+b-c)+b(a+b-c)+c(a+b-c)
=a²+ab-ac+ba+b²-bc+ca+cb-c²
=a²+b²-c²+2ab
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