Question

simplify a.b.c+a.b'.c+a.c' by boolean algebra​

Answer 1

Answer:

expression is: AB+A(¬C)+BC=AB(C+(¬C))+A(¬C)(B+(¬B))+BC(A+(¬A))=ABC+AB(¬C)+AB(¬C)+A(¬B)(¬C)+ABC+(¬A)BC=ABC+AB(¬C)+A(¬B)(¬C)+(¬A)BC=BC(A+(¬A))+A(¬C)(B+(¬B))=BC+A(¬C)