simplify: (a+b) (c-d) + (a-b) (c+d) +2(ac+bd)
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(a + b) (c-d) + (a−b) (c+d) +2 (ac+bd)
Simplifying, (a + b) (c-d) + (a−b) (c+d) +2 (ac+bd)
= ac - ad+bc-bd + ac bd-bc+ad+2ac+2bd
We multiply each element of these two binomials.
Calculating the ac ad + bc
bd + ac - bd-bc+ad + 2ac +2bd
ac - ad + bc-- bd- bc+ad+ 2ac +bd =4ac
calculated like terms.
Hence, the simplification of (a + b) (c-d) + (a−b) (c+d) +2 (ac+bd) is
4ac
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