Simplify a plus b a minus 3 b + c minus 2 a - 3 b whole c
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Step-by-step explanation:
Given Simplify a plus b 2a minus 3 b + c minus (2 a - 3 b )c
- Given (a + b)(2a – 3b + c) – (2a – 3b)c
- Now multiplying we get
- So a (2a – 3b + c) + b(2a – 3b + c) – (2a – 3b)c
- = 2a^2 – 3ab + ac + 2ab – 3b^2 + bc – 2ac + 3bc
- = 2a^2 – 3b^2 + (- 3 + 2)ab + (1 + 3) bc + (1 – 2) ac
- = 2a^2 – 3b^2 – ab + 4bc - ac
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