Question

Simplify(a square -b square )cube +(b square-square)cube+(c square-a square) cube/(a-b)cube(b-c)cube+(c-a)cube

Answer 1

Solution:

/* we know that,

if x+y+z = 0 then x³+y³+z³ = 3xyz */

i) [(a²-b²)³+(b²-c²)³+(c²-a²)]/[(a-b)³+(b-c)³+(c-a)³]

= [3(a²-b²)(b²-c²)(c²-a²)]/[3(a-b)(b-c)(c-a)]

=[(a+b)(a-b)(b+c)(b-c)(c+a)(c-a)]/[(a-b)(b-c)(c-a)]

After cancellation,we get

= (a+b)(b+c)(c+a)

••••

Answer 2

Answer:don't know

Step-by-step explanation: