Question

Simplify : (a²-b²)³+(b²-c²)³+(c²-a²)
÷(a-b)³+(b-c)³+(c-a)³

Answer 1

Hope this may help you please mark me as brainliest

Answer 2

we use the fact that if a+b+c = 0 then
a³+b³+c³ = 3abc

(a²-b²)+(b²-c²)+(c²-a²) = 0
also (a-b)+(b-c)+(c-a) = 0
we assume that a ≠ b ≠c

hence
: (a²-b²)³+(b²-c²)³+(c²-a²)³
÷(a-b)³+(b-c)³+(c-a)³

= 3(a²-b²)(b²-c²)(c²-a²) / 3(a-b) (b-c) (c-a)
=(a+b)(b+c)(c+a)
bcoz a²-b² = (a+b)(a-b) and similarly other terms...


Hope it'll help you my friend :)