Question

simplify:- a⁴×b⁵× c⁷ upon c⁸×a⁴×b³​

Answer 1

Answer:

The answer is $b^{2} c^{-1}$

Step-by-step explanation:

It is given that $\frac{a^{4}b^{5}c^{7}}{c^{8}a^{4}b^{3} }$

We can separate it is

$\frac{a^{4}}{a^{4} } \frac{b^{5}}{b^{3} } \frac{c^{7}}{c^{8} }$

As they are in division and the base is same, hence the powers will be subtracted.

Hence, $1b^{5-3} c^{7-8}$

Hence, we get

$b^{2} c^{-1}$

#SPJ3

Answer 2

Answer:

simplified form : b²/c

Given: A fraction a⁴×b⁵×c⁷÷c⁸× a⁴×b³

To find: simplified form .

Solution:  we can simplify by applying properties of exponential functions.

          $\frac{a^{4}*b^{5}*c^{7} }{c^{8}*a^{4}*b^{3} }$       = $\frac{a^{4}*a^{4}*b^{5}*c^{7} }{c^{8}*b^{3} }$

                             = $\frac{(a*a)^{4-4}*b^{5}*c^{7} }{c^{8}*b^{3} }$      ( by property mᵃ/mᵇ = mᵃ-ᵇ)

                             = $\frac{a^{0}*b^{5} *c^{7} }{c^{8}*b^{3} }$

                             = $\frac{1*(b^{5-3})*c^{7} }{c^{8} }$             (by same property)

                             = $\frac{b^{2}*c^{7} }{c^{8} }$

                             = $b^{2}*c^{(7-8)}$

                             = $b^{2} *c^{-1}$

                             = $b^{2}*\frac{1}{c}$                    

Therefore   $\frac{a^{4} *b^{5}*c^{7} }{c^{8}*a^{4}*b^{3} }$   = $\frac{b^{ 2 } }{ c }$

#SPJ2