simplify: ab(ab + bc + cd) + bc(bc + cd + ab)
if anyone solve this question so please write down the answer thank you
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Answer:
(ab)square+(bc)square+c square bd+abcd+2a b square c
Step-by-step explanation:
ab(ab+bc+cd) + bc (bc+cd+ab)
ab (ab+bc+cd)=
(ab)square+b square ac+ abcd
bc (bc+cd+ab)=
(bc)square+c square bd+abcd
(ab)square+b square ac+ abcd+(bc)square+c square bd+abcd = (ab)square+(bc)square+c square bd+abcd+2a b square c
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