simplify (ab+bc)²-2ab²c
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Answer:
b²(a²+c²)
Step-by-step explanation:
(ab+bc)²-2ab²c
Expanding (ab+bc)² with the identity (a+b)²:
=(ab)²+2*(ab)*(bc)+(bc)²-2ab²c
=a²b²+2ab²c+b²c²-2ab²c
2ab²c and (-2ab²c) cancel out each other
=a²b²+b²c²
Taking b² common between both the terms:
=b²(a²+c²)
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