simplify (ab+bc)²-2ab²c
ahmed8157:
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Answered by
2
Answer:
(ab+bc)²-2ab²c
a²b²+b²c²+2ab²c-2ab²c. {use(a+b)²=a²+b²+2ab}
a²b²+b²c²
this is ur required ans
Answered by
0
Given, (ab+bc)2−2ab2c.
We know,
(a+b)2=a2+2ab+b2.
Then,
(ab+bc)2−2ab2c
=(ab)2+2(ab)(bc)+(bc)2−2ab2c
=a2b2+2ab2c+b2c2−2ab2c
=a2b2+b2c2.
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