Question

simplify (ab+ bc)² - 2ab²c​

Answer 1

Step-by-step explanation:

a²b²+ b²c²+2ab²c-2ab²c

$\longrightarrow \: {a}^{2} {b}^{2} + {b}^{2} {c}^{2}$

$\longrightarrow \: {b}^{2} ( {a}^{2} + {c}^{2} )$

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Answer 2

(ab+bc)²−2ab²c

Distribute:

=ab²+2ab²c+b²c²+−2ab²c

Combine Like Terms:

=a²b²+2ab²c+b²c²+−2ab²c

=(a²b²)+(2ab²c+−2ab²c)+(b²c²)

=a²b²+b²c²