SIMPLIFY
(AB'C(C+BD)+A'B')C
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Since the entire expression is ANDed with C, we know that when C=0 the expression is 0.
When C=1 the expression simplifies to
AB’(1+BD) + A’B’ = AB’+A’B’ = (A+A’)B’ = B’
So the final expression simplifies to B’C
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