Question

simplify
-abc (abc-a²bc-ab²c) - ab (-a²bc + b²ca-c²ab)​

Answer 1

Answer:

a^2bc+ab^2+abc^2

take abc as common,

=abc [a^2bc/abc+ab^2c/abc+abc^2/abc]

=abc{a+b+c}

hence,the factores form abc=abc(a+b+c)