Question

simplify & rationalise the following
$\frac{ \sqrt{2} + \sqrt{3} }{ \sqrt[3]{2} - \sqrt[2]{3} } = 2 - b \sqrt{6}$
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Answer 1

by the way the question is wrong

as ^2√3 is equal to √3

how the question is made.

the real question is

(√2+√3)/(3√2-2√3) = 2-b√6

rationalize it

(√2+√3)(3√2+2√3) / ( 3√2-2√3)(3√2+2√3) = 6+2√6+3√6+ 6/ 18-12 = 2-b√6 (12+5√6)/6=2-b√6

12+5√6= 6(2-b√6)

12+5√6 = 12-6b√6

5√6 =- 6b √ 6

5 = -6b

b = -5/6

is I am correct ✅ or not