Simplify and also write laws which are used to simplify this (3⁻⁴× 10⁻²×81×2² ×125) ⁄ 5
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Step-by-step explanation:
Given:-
(3^-4× 10^-2×81×2^2×125) ⁄ 5
To find:-
simplify this (3^-4× 10^-2×81×2^2×125) ⁄ 5
Solution:-
Given expression is (3^-4× 10^-2×81×2^2×125) ⁄ 5
It can be written as
=>(3^-4×10^-2×3^4×2^2×5^3)/5
We know that
a^-n = 1/a^n
=>[(1/3)^4×(1/10)^2×3^4×2^2×5^3]/5
=>[(1/3)^4×(1/2)^2×(1/5)^2×3^4×2^2×5^3]/5
It can be written as
=>[(3^4/3^4 )×(5^3/5^2)×(2^2/2^2)]/5
We know that a^m/a^n = a^(m-n)
= [3^(4-4)×5^(3-2)×2^(2-2)]/5
=>(3^0×5^1×2^0)/5
We know that a^0 = 1
=>(1×5×1)/5
=>5/5
=>1
Answer:-
The value of the given expression is 1
Used formulae:-
- a^-m = 1/a^m
- a^m/a^n = a^(m-n)
- a^0 = 1
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