Math, asked by deiineideilamlhangha, 7 months ago

Simplify and answer each of the following in ​

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Answered by Mihir1001
1

\huge{\underline{\mathfrak{\textcolor{blue}{Answer :}}}}

\huge\boxed{\fcolorbox{red}{pink}{answer}}

\huge{\underline{\mathrm{\textcolor{red}{Step-by-step \:  \: explanation :}}}}

\LARGE{\underline{\mathtt{\textcolor{violet}{Given :-}}}}

  • ( a ) \Large{ { \left(  \frac{ - 3}{31}  \right) }^{5}  \times  { \left(  \frac{ - 3}{31}  \right) }^{4}  \div  { \left(  \frac{ - 3}{31}  \right) }^{8} }

  • ( b ) \Large{ { \left[  {( - 3)}^{2}  \right] }^{3}  \times  \frac{1}{ { \left[  {( - 3)}^{3}  \right] }^{2} } }

  • ( c ) \Large{ \left(  {5}^{17}  \times  {5}^{19}  \right)  \div  {5}^{37} }

  • ( d ) \Large{ \left[  { \left(  \frac{ - 2}{5}  \right) }^{7}  \div  { \left(  \frac{ - 2}{5}  \right) }^{3}  \right]  \times  { \left(  \frac{ - 2}{5}  \right) }^{2} }

\LARGE{\underline{\mathtt{\textcolor{green}{To \:  \: find :-}}}}

  • Simplify all ( a ) , ( b ) , ( c ) and ( d ) .

\LARGE{\underline{\mathtt{\textcolor{teal}{Concept \:  \: used :-}}}}

  • Simplification, and
  • Exponentiation

\LARGE{\underline{\mathtt{\textcolor{blue}{Solution :-}}}}

\Large\boxed{a}\Large{ { \left(  \frac{ - 3}{31}  \right) }^{5}  \times  { \left(  \frac{ - 3}{31}  \right) }^{4}  \div  { \left(  \frac{ - 3}{31}  \right) }^{8} }

\Large{ =  { \left(  \frac{ - 3}{31}  \right) }^{5 + 4 - 8} }

\Large{ =  { \left(  \frac{ - 3}{31}  \right) }^{10 - 8} }

\Large{ =  { \left(  \frac{ - 3}{31}  \right) }^{2} }

\Large{ =  \frac{ {( - 3)}^{2} }{ {(31)}^{2} } }

\Large{ =  \frac{9}{961} }

\Large\boxed{b}\Large{ { \left{  {( - 3)}^{2}  \right} }^{3}  \times  \frac{1}{ { \left{ {  {( - 3)}^{3}  \right} }^{2} } } }

\Large{ =  {( - 3)}^{2 \times 3}  \times  \frac{1}{ {( - 3)}^{3 \times 2} } }

\Large{ =  {( - 3)}^{6}  \times  \frac{1}{ {( - 3)}^{6} } }

\Large{ =  \cancel{ {( - 3)}^{6} }  \times  \frac{1}{ \cancel{ {( - 3)}^{6} } } }

\Large{ = 1 \times  \frac{1}{1} }

\Large{ = 1}

\Large\boxed{c}\Large{ \left(  {5}^{17}  \times  {5}^{19}  \right)  \div  {5}^{37} }

\Large{ =  \left(  {5}^{17 + 19}  \right)  \div  {5}^{37} }

\Large{ =  \left(  {5}^{36}  \right)  \div  {5}^{37} }

\Large{ =  {5}^{36}  \div  {5}^{37} }

\Large{ =  {5}^{36 - 37} }

\Large{ =  {5}^{ - 1} }

\Large{ =  \frac{1}{5} }

\Large{ = 0.2}

\Large\boxed{d}\Large{ \left[  { \left(  \frac{ - 2}{5}  \right) }^{7}  \div  { \left(  \frac{ - 2}{5}  \right) }^{3}  \right]  \times  { \left(  \frac{ - 2}{5}  \right) }^{2} }

\Large{ =  \left{  { \left(  \frac{ - 2}{5}  \right) }^{7 - 3}  \right}  \times  { \left(  \frac{ - 2}{5}  \right) }^{2} }

\Large{ =  \left{  { \left(  \frac{ - 2}{5}  \right) }^{4}  \right}  \times  { \left(  \frac{ - 2}{5}  \right) }^{2} }

\Large{ =  { \left(  \frac{ - 2}{5}  \right) }^{4}  \times  { \left(  \frac{ - 2}{5}  \right) }^{2} }

\Large{ =  { \left(  \frac{ - 2}{5}  \right) }^{4 + 2} }

\Large{ =  { \left(  \frac{ - 2}{5}  \right) }^{6} }

\Large{ =  \frac{ {( - 2)}^{6} }{ {(5)}^{6} } }

\Large{ =  \frac{64}{15625} }

\LARGE{\underline{\mathtt{\textcolor{magenta}{Conclusion :-}}}}

  • \Large{( \: a \: ) \:  \frac{9}{961} }

  • \Large{( \: b \: ) \:  1}

  • \Large{( \: c \: ) \:  0.2}

  • \Large{( \: d \: ) \:  \frac{64}{15625} }

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