Question

Simplify and evaluate for b=0 and c=2 (9b²c-4c²)(2bc²+5c)​

Answer 1

Answer:

-160

Step-by-step explanation:

b=0,c=2

(9b²c-4c²)(2bc²+5c)

(9×0²×2-4×2²)(2×0×2²+5×2)

(0-16) (0+10)

-16×10 = -160