simplify and expand (1+i)^2(3-4i)
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Solution:
=> (1 + i)² (3 - 4i)
=> (1 + i² + 2i) (3 - 4i)
=> (1 - 1 + 2i) (3 - 4i)
=> 2i (3 - 4i)
=> 6i - 8i²
=> 8 + 6i
Here, Real part is 8 and imaginary part is 6.
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Extra information:
z = a + bi
Here z represents the complex number a represents the real part of the number and b represents the imaginary part of the number. i (called as iota) = √-1.
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