Math, asked by dakshspecialjain, 10 months ago

simplify and express in power notation. (81/16)^(-1/2) × (2/3)^2 ÷ (3/2)^(-2)​

Answers

Answered by AsifaJavid
1

Step-by-step explanation:

Evaluate:

(i) 3-2 (ii) (-4)-2 (iii) (1/2)-5

Answer:

(i) 3-2 = 1/32 = 1/9 [a-m = 1/ am]

(ii) (-4)-2 = 1/42 = 1/16 [a-m = 1/ am]

(iii) (1/2)-5 = (2/1)5 = 25 = 32 [a-m = 1/ am]

Question 2:

Simplify and express the result in power notation with positive exponent:

(i) (-4)5 ÷ (-4)8 (ii) (1/23)2 (iii) (-3)4 * (5/3)4 (iv) (3-7 * 3-10) * 35

(v) 2-3 * (-7)3

Answer:

(i) (-4)5 ÷ (-4)8 = (-4)5-8 [am ÷ an = am-n]

= (-4)-3

= 1/(-4)3 [a-m = 1/ am]

= -1/64

(ii) (1/23)2 = 12/(23)2 [(a/b)m = am/bm]

= 1/ 23*2 [(am)n = am*n]

= 1/26

= 1/64

(iii) (-3)4 * (5/3)4 = (-3)4 * (54/34 ) [(a/b)m = am/bm]

= (3)4 * (54/34 ) [(-a)m = am when m is an even number]

= (3)4-4 * 54

= 54

(iv) (3-7 * 3-10) * 35 = 3-7-10+5 [am * an = am+n]

= 3-17+5

= 3-12

= 1/312 [a-m = 1/ am]

(v) 2-3 * (-7)-3 = 1/23 * 1/(-7)-3 [a-m = 1/ am]

= 1/{(-7)3 * 23 }

= 1/(-7 * 2)3 [am * bm = (a * b)m]

= 1/(-14)3

= -1/(14)3 [(-a)m = -am when m is an odd number]

Question 3:

Find the value of:

(i) (30 + 4-1) * 22 (ii) (2-1 * 4-1) ÷ 2-2 (iii) (1/2)-2 + (1/3)-2 + (1/4)-2

(iv) (3-1 + 4-1 + 5-1)0 (v) {(-2/3)-2}2

Answer:

(i) (30 + 4-1) * 22 = (1 + 1/4) * 22 [a0 = 1 and a-m = 1/ am]

= (5/4) * 22

= (5/22) * 22

= 5 * 22-2 [am ÷ an = am-n]

= 5 * 20

= 5 * 1

= 5

(ii) (2-1 * 4-1) ÷ 2-2 = (1/2 * 1/4) ÷ 2-2 [a-m = 1/ am]

= (1/8) ÷ 2-2

= (1/8) ÷ 2-2

= (1/23) ÷ 2-2

= 2-3 ÷ 2-2

= 2-3 * 1/2-2

= 2-3+2 [am ÷ an = am-n]

= 2-1

= 1/2 [a-m = 1/ am]

(iii) (1/2)-2 + (1/3)-2 + (1/4)-2 = (2/1)2 + (3/1)2 + (4/1)2 [a-m = 1/ am]

= 22 + 32 + 42

= 4 + 9 + 16

= 29

(iv) (3-1 + 4-1 + 5-1)0 = 1 [(a + b)0 = 1]

(v) {(-2/3)-2}2 = {(-3/2)2}2 [a-m = 1/ am]

= (-3/2)2*2 [(am)n = am*n]

= (-3/2)4

= (-3)4/24

= 81/16

Question 4:

Evaluate:

(i) (8-1 * 53)/2-4 (ii) (5-1 * 2-1) * 6-1

Answer:

(i) (8-1 * 53)/2-4 = {(23)-1 * 53}/2-4

= (2-3 * 53)/2-4 [(am)n = am*n]

= (2-3+4 * 53) [am ÷ an = am-n]

= 2 * 53

= 2 * 125

= 250

(ii) (5-1 * 2-1) * 6-1 = (1/5 * 1/2) * 1/6 [a-m = 1/ am]

= 1/10 * 1/6

= 1/60

Question 5:

Find the value of m for which 5m ÷ 5-3 = 55

Answer:

Given, 5m ÷ 5-3 = 55

=> 5m-(-3) = 53 [am ÷ an = am-n]

=> 5m+3 = 55

Comparing exponent on both sides, we get

=> m + 3 = 5

=> m = 5 -3

=> m = 2

Question 6:

Evaluate:

(i) {(1/3)-1 + (1/4)-1}-1 (ii) (5/8)-7 * (8/5)-4

Answer:

(i) {(1/3)-1 - (1/4)-1}-1 = {(3/1)1 - (4/1)1}-1 [a-m = 1/ am]

= (3 - 4)-1

= (-1)-1

= 1/(-1) [a-m = 1/ am]

= -1

(ii) (5/8)-7 * (8/5)-4 = 5-7/8-7 * 8-4/5-4 [a-m = 1/ am]

= 5-7+4 * 8-4-(-7) [am ÷ an = am-n]

= 5-3 * 83

= 83/53 [a-m = 1/ am]

= 512/125

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