Question

Simplify and factorise
(a+2b+3c)²-(a-2b-3c)²-6b²-9bc

Answer 1

Answer:

(a+2b+3c)  

2

−(a−2b+3c)  

2

−6b  

2

−abc

=a  

2

+4b  

2

+9c  

2

+4ab+12bc+6ac−(a  

2

+4b  

2

+9c  

2

−4ab−12bc+6ac)−6b  

2

−9ac

=a  

2

+4b  

2

+9c  

2

+4ab+12ac+6ac−a  

2

−4b  

2

−ac  

2

+4ab+12bc−6ac−6b  

2

−9bc

=8ab+24bc−6b  

2

−9bc

Step-by-step explanation:

Answer 2

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