Question

simplify and factorise: (a+3b+3c)^2 - (a-2b-3c)^2 -6b^2 -9bc

Answer 1

Answer:

Step-by-step explanation

=a^2+9 b^2+9 c^2+ 2(3 ab+9 bc+3 ca) - {a^2+4 b^2+9 c^2+ 2(-2 ab+6 bc

-3 ca)}-36 b^4-9 bc

=a^2+9 b^2+9 c^2+6 ab + 18 bc+6 ca- {a^2+4 b^2+9 c^2 -4 ab +12 bc

-6 ca}-36 b^4-9 bc

=a^2+9 b^2+9 c^2+6 ab + 18 bc+6 ca- a^2-4 b^2-9 c^2 +4 ab -12 bc

+6 ca-36 b^4-9 bc

= 5 b^2+10 ab-3 bc+12 ca(ANS)

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