Question

simplify and factorise a + b + C whole square minus a minus b minus C whole square + 4 b square - 4 c square​

Answer 1

Answer:

4(b+c)(a+b-c)

Step-by-step explanation:

(a+b+c)²-(a-b-c)²+4b²-4c²

= [(a+b+c)+(a-b-c)][(a+b+c)-(a-b-c)]+4(b²-c²)

/* By algebraic identity:

x²-y² = (x+y)(x-y) */

=(a+b+c+a-b-c)(a+b+c-a+b+c)+4(b+c)(b-c)

= 2a(2b+2c)+4(b+c)(b-c)

= 4a(b+c)+4(b+c)(b-c)

= 4(b+c)(a+b-c)

Therefore,

(a+b+c)²-(a-b-c)²+4b²-4c²

= 4(b+c)(a+b-c)

•••♪

Answer 2

Answer:

simplify and factorise a + b + C whole square minus a minus b minus C whole square + 4 b square - 4 c square