Math, asked by jeetu6483, 2 months ago

Simplify and find the value of 3a (a b)-2ab(a-b) + ab(a-b) for a= -1,b= 2​

Answers

Answered by usernametaken8
0

Answer:

3

Step-by-step explanation:

3a(a-b) -2ab(a-b) + ab(a-b)

= (a-b)(3a-2ab+ab)

=(a-b)(3a-ab)

=a(a-b)(3-b)

for a=-1 and b=2

-1 × (-1-2)(3-2) = -1×-3×1 = 3

Answered by latabara97
0

Answer:

Given, (ab+bc) ² − 2 ab²c.

We know,

(a+b)² =a²+2ab+b²

Then,(ab+bc)² - 2ab²c

=(ab)² +2ab²c + b² c²−2ab²c

=a² b² +b²c ².

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