Math, asked by sreenidhivarma07, 1 month ago

Simplify and rationalise the denominator of 3√27 ÷ 6√20.

Answers

Answered by TigerMan28
1

Answer:

1215 / 80

Step-by-step explanation:

 \frac{3 \sqrt{27} }{6 \sqrt{20} }  \\  =  \frac{3 \times 3 \sqrt{3} }{6 \times 2 \sqrt{5} }  \\  =  \frac{3 \sqrt{3} }{4 \sqrt{5} }   \\  =  \frac{3 \sqrt{3} }{4 \sqrt{5} }  \times  \frac{\sqrt{5} }{\sqrt{5} }  \\  =  \frac{</em></strong><strong><em> </em></strong><strong><em>3</em></strong><strong><em>\sqrt{15} }{</em></strong><strong><em>2</em></strong><strong><em>0</em></strong><strong><em>}

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