Question

Simplify and solve linear equations: 15(y-4)-2(y-9)+5(y+6)=0​

Answer 1

$\huge\purple{ \underline{ \boxed{\mathbb{\red{QUESTION : }}}}}$

$\small \textsf{Solve: 15 ( y - 4) - 2 ( y - 9) + 5 ( y + 6 ) = 0}$

$\huge\purple{ \underline{ \boxed{\mathbb{\red{ANSWER : }}}}}$

$\large\displaystyle { \color{red} \sf y = \frac{2}{3} }$

$\green{ \large \underline{ \mathbb{\underline{GIVEN : }}}}$

$\textsf{15 ( y - 4) - 2 ( y - 9) + 5 ( y + 6 ) = 0}$

$\green{ \large \underline{ \mathbb{\underline{TO \: FIND : }}}}$

$\red{ \overline\textsf{\underline{Value of y .}}}$

$\green{ \large \underline{ \mathbb{\underline{SOLUTION: }}}}$

$\begin{array}{l} \\ \hline \\ \small \sf{15 ( y - 4) - 2 ( y - 9) + 5 ( y + 6 ) = 0} \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\\ \\\small \sf15y - 60 - 2y + 18 + 5y + 30 = 0 \\ \\ \small \sf15y - 2y + 5y - 60 + 18 + 30 = 0 \\ \\ \small \sf13y + 5y - 60 + 48 = 0 \\ \\ \small \sf18y - 12 = 0 \\ \\ \small \sf18y = 12 \\ \\ \small \displaystyle\sf y = \frac{12}{18} \\ \\ \small \displaystyle\sf y = \frac{2}{3} \\ \\ \hline\\ \end{array}$

Answer 2

Step-by-step explanation:

given linear equation

$15(y + 4) - 2(y - 9) + 5(y + 6) = 0$

to find value of varaible y

solution

simplify by solving brackets

$15y + 60 - 2y - 18 + 5y + 30 = 0$

add the numbers

$15y - 12 - 2y + 5y = 0$

combine like term

$18y - 12 = 0$

add 12 on both side of equation

$18y - 12 + 12 = 0 + 12$

simplify

$18y = 12$

divide both side by same term

$\frac{18y}{18} = \frac{12}{18}$

simplify

$y = \frac{2}{3}$

hence value of variable y is

$\frac{2}{3}$