Question

Simplify and solve the following linear equation. 
12(y–4)–2(y–6)+3(y+4)=0 ​

Answer 1

Answer:

6

Step-by-step explanation:

12y-48-2y+12+3y+12=0

12y-2y+3y=48-12-12

7y=48

y=48/7

y=6

HOPE THIS IS HELPFUL TO YOU

Answer 2

According to the information provided in the preceding question,

The supplied value is as follows:

12(y–4)–2(y–6)+3(y+4)=0 ​ is the provided question.

We have to find the value of the above equation.

Here we have to use the BODMAS rule.

Thus, solving the given equation we get,

$12(y-4)-2(y-6)+3(y+4)=0\\12y-48-2y+12+3y+12=0\\12y-2y+3y-48+12+12=0\\13y-24=0$

Solving equation further we get,

$13y=24\\y=\frac{24}{13}\\y=1.85$

Hence the value of y is 1.85