Question

simplify and solve the following
linear equation
. 3(t-3)=5(2t+1)​

Answer 1

Given equation:

3(t-3) = 5(2t+1)

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Solution:

3(t-3) = 5(2t+1)

3t-9 = 10t+5

-9-5 = 10t-3t

-14 = 7t

$\dfrac{ - 14}{7} = t$

$\boxed{\boxed {\sf {\red {-2 = t}}}}$

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Verification:

On substituting the value of t as -2 in the equation,

3(t-3) = 5(2t+1)

3(-2-3) = 5[2×(-2)+1]

3×(-5) = 5(-4+1)

-15 = 5×(-3)

-15 = -15

LHS = RHS

Hence Verified!

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Final answer:

The value of t is $\sf \purple {(-2)}$.

Answer 2

Step-by-step explanation:

given equation

$3(t - 3) = 5(2t + 1)$

simplify equation by solving brackets

$3t - 9 = 10t + 5$

solve equation

$7t = - 14$

$t = \frac{ - 17}{2}$

hence value of variable t is -2.