Math, asked by kaushiki14, 9 months ago

simplify and solve the following linear equations-
0.25(4y-1)=0.05(10y-1)​

Answers

Answered by jagriti1188
0

Answer:

0.4

Step-by-step explanation:

0.25(4y-1)=0.05(10y-1)

 =  > 1y - 0.25 = 0.5y - 0.05

 =  > 1y - 0.5y = 0.25 - 0.05

 =  > 0.5y = 0.20

 =  > y =  \frac{0.20}{0.5}

 =  > y =  \frac{20}{100}  \times  \frac{10}{5}

 =  > y =  \frac{4}{10}

 =  > y = 0.4

I hope this helped you

Answered by shaswat8080
0

Step-by-step explanation:

given linear equation is

0.25(4y - 1) = 0.05(10y - 1)

to find value of variable y

solution

simplify equation by solving brackets

y - 0.25 = 0.5y - 0.05

solving similar terms

y - 0.5y =  - 0.05 + 0.25

0.5y = 0.2

y =  \frac{0.2}{0.5}

hence value of variable y is 0.4.

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