Question

simplify and. verify the result for x=2 and y=-1 6x²+(x+3y)(3-2y)

Answer 1

Given: x = 2 and y = -1.

To find: 6x²+(x+3y)(3-2y) when substituting the values and verify it.

Answer:

Let us substitute the given values in 6x²+(x+3y)(3-2y).

6*(2)^2 + (2 + 3*(-1))(3 - 2*(-1))

6*4 + (2 - 3)(3 + 2)

24 - 1*5

24 - 5

= 19.

When verifying it,

LHS = 6*(2)^2 + (2 + 3*(-1))(3 - 2*(-1)) = RHS

Hope it helps :)

Answer 2

♠ REFER THE CLIPPING.