Question

Simplify and write in exponential form
((-2)^3)^2+5^-3÷5^-5-(-1/2)^0
​

Answer 1

((-2)^3)^2+5^-3÷5^-5-(-1/2)^0

=(-8)^2+5^((-3-(-5))-1

=64+5^(-3+5)-1

=64+5^2-1

=64+25-1

=88

Answer 2

The required form is $((-2)^3)^2+5^{-3}\div 5^{-5}-(-\frac{1}{2})^0=(88)^1$

Step-by-step explanation:

Given : Expression $((-2)^3)^2+5^{-3}\div 5^{-5}-(-\frac{1}{2})^0</p><p>$

To find : Simplify the expression ?

Solution :

$((-2)^3)^2+5^{-3}\div 5^{-5}-(-\frac{1}{2})^0$

$=(-8)^2+5^{-3-(-5)}-1$

$=64+5^(-3+5)-1$

$=64+5^2-1$

$=64+25-1$

$=88$

In exponential form, $=(88)^1$

Therefore, the required form is $((-2)^3)^2+5^{-3}\div 5^{-5}-(-\frac{1}{2})^0=(88)^1$

#Learn more

Simplify: √(3+2√2)

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