Question

Simplify and write in exponential form with positive exponents of [{(5/7)^2}^-1]^-3

Answer 1

Answer:

It is very easy

[{(5/7)^2}^-1]^-3= (5/7)^ 2*-1*-3  ( since powers on one integer are multiplied)

Ans.

(5/7)^6

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

[{(5/7)^2}^-3]^-1

= (5/7)^[2*(-3)(-1)]

= (5/7)^6

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