Question

simplify and write the answer in exponential form (2^5/2^8)^5 x 2^-5

Answer 1

hey user here is your answer in the pic ....
hope it helps you !!!!!

Answer 2

Answer:

$\big(\frac{2^{5}}{2^{8}}\big)^5\times 2^{-5}=\frac{1}{2^{20}}$

Step-by-step explanation:

$Given \: \big(\frac{2^{5}}{2^{8}}\big)^5\times 2^{-5}$

$=\big(\frac{1}{2^{8-5}}\big)^5\times 2^{-5}$

$By \: exponential law:\\\frac{a^{m}}{a^{n}}=\frac{1}{a^{n-m}}$

$=\big(\frac{1}{2^{3}}\big)^5\times 2^{-5}$

$=\big(\frac{1}{2^{3\times 5}}\big)\times 2^{-5}$

$By \: exponential law:\\(a^{m})^{n}=a^{mn}$

$=\big(\frac{1}{2^{15}}\big)\times 2^{-5}$

$=\frac{2^{-5}}{2^{15}}$

$=\frac{1}{2^{15+5}}$

$=\frac{1}{2^{20}}$

Therefore,

$\big(\frac{2^{5}}{2^{8}}\big)^5\times 2^{-5}=\frac{1}{2^{20}}$

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