Question

simplify as soon as possible.... pls​

Answer 1

Answer:

Step-by-step explanation:

x + y + z = 0

x³ + y³ + z³ = 3xyz

Let x = a² - b² ,

y = b² - c²

z = c² - a²

x + y + z = a² - b² + b² - c² + c² - a²

= 0

so,

( a² - b² )³ + ( b² - c² )³ + ( c² - a² )³

= 3( a² - b² )( b² - c² )( c² - a² ) ---( 1 )

Similarly ,

( a - b )³ + ( b - c )³ + ( c - a )³

= 3( a - b )( b - c )( c - a ) ----( 2 )

( 1 ) divide  ( 2 )

=[3(a²-b²)(b²-c²)(c²-a²)]/[3(a-b)(b-c)(c-a)]

= ( a + b )( b + c )( c + a )

Answer 2

(A+B) (B+C) (C+A)

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