simplify b) 3‐½× 3‐⅕
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ßõlûtîôñ= thêrê ïß 3 whé çâñ wrïte it à 3/1-1/2 déñômîñåtôr ãrê dîffrènt whê çåñ takê LCM of 1,2 LCM is 1 dîvîdê ít by denómìñátór and multiply by numreater 1/1 équal to 1 and 2/1 is 1 1+2/1 = 3/1. then same we can write 3 as 3+1 LCM of denominator 1 and 5 is 5. is 5 and 5+1/5 is 6/5 and plus 3/1+6/5 take LCM LCM is 5 dive by deno minator is 5 and 1 and multiplay with denominator 15+6\5 = 21\5 áß yóú dóñt míñd mârk mé âß bráíñlîßt
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