Math, asked by Anonymous, 9 months ago

Simplify b^3 + b^2. Answers that do not explain clearly from basic steps will be reported.

Answers

Answered by shrinijarvis
1

= (b^{3} + b^{2} )

= b^{2} (b  + 1)

= { take b as common bas outside brackets. by doing so b^{2} will come out. then when b^{2} is multiplied to b we get b^{3} and when b^{2} is multiplied to 1 we get b^{2} }

to find the solution equate it to zero.

= b^{2} (b  + 1) = 0\\

b^{2}  = 0           and      b + 1 = 0

b = \sqrt{0} = 0   and       b = -1

PLEASE MARK AS BRAINLIEST

Similar questions