Question

simplify b2-(b-1)(b+2 )/3 = 1/5 ​

Answer 1

b2-(b-1)(b+2)/3=1/5

b2-(b-1)(b+2)=3/5

b2-b+1(b+2)=3/5

b2-b^2-b2+b+2=3/5((b^2=b sq))

-b^2+b+2=3/5

-b^2+b=3/5-2

-b^2+b= -7/5

-b^2+b+7/5=0

-5b^2+5b+7=0

take - common

5b^2+5b+7=0