simplify (b²+c²)-[b²-b(b+c)+c²]
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Answer:
b²+bc
Step-by-step explanation:
(b²+c²)-[b²-b(b+c)+c²
=(b²+c²)-[b²-b²-bc)+c²]
=b²+c²-c²+bc
=b²+bc
Hope , u find this useful !
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