Question

simplify by combining similar terms​

Answer 1

Answer:

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Step-by-step explanation:

$¥PH€Rururuurjrur

Answer 2

Answer:

Step-by-step explanation:

( 1 ) 3 √45 - √125 + √200 - √50

= 3 (√9 × 5) - (√25 × 5) + (√100 × 2) - (√25 × 2)

= 3 (√9 × √5) - (√25 × √5) + (√100 × √2) - (√25 × √2)

= 3 × 3 (√5) - (5 × √5) + (10 × √2) - (5 × √2)

= 9 √5 - 5 √5 + 10 √2 - 5 √2

= ( 9 - 5 ) √5 + ( 10 - 5 ) √2

= 4 √5 + 5 √2 is the answer.

( 2 ) ( 2 × 3√54 ) + ( 3 × 3√16 ) + ( 5 × 3√128 )

= ( 2 × 3√2×3×3×3 ) + ( 3 × 3√2×2×2×2 ) + ( 5 × 3√2×2×2×2×2×2×2 )

= ( 2 × 3√2×3^3 ) + (3 × 3√2×2^3 ) + ( 5 × 3√2^3 × 2^3 × 2 ) (∵"^" it means to the power of )

= [ 2 × 3 √2 × (3^3)^1/3 ] + [ 3 × 3 √2 × (2^3)^1/3 ] + [ 5 × 3 √(2^3)^1/3 × ( 2^3)^1/3 × 2] [ ∵ (3^3)^1/3 = (3)^3×1/3 powers 3 and 1/3 are cancelled, we get only 3. And (2^3)^1/3 = (2)^3×1/3 powers 3 and 1/3 are cancelled, we get only 2.]

= ( 2 × 3 × 3√2 ) + ( 3 × 2 × 3√2 ) + ( 5 × 2 × 2 × 3√2 )

=( 6 × 3√2 ) + ( 6 × 3√2 ) + ( 20 × 3√2 )

= ( 6 + 6 + 20 ) × 3√2

= 32 × 3√2

= 32 3√2 is the answer.