Simplify by factorisation method:6-2√2x-x^2/2-x^2
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roots=(-b+_√b^2-4ac)/2a
given equation=-(3x^2/2+2√2x-6)
root1=(-2√2+√8+36)/3
root1=(-2√2+√44)/3
root2=(-2√2-√44)/3
original root1(by negative sign)=(2√2-√44)/3
root2=(2√2+√44)/3
given equation=-(3x^2/2+2√2x-6)
root1=(-2√2+√8+36)/3
root1=(-2√2+√44)/3
root2=(-2√2-√44)/3
original root1(by negative sign)=(2√2-√44)/3
root2=(2√2+√44)/3
kirannaidu137:
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yeah
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