Question

simplify by factorisation method:-
9-2√3x-x2/3-x2​

Answer 1

Answer:

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(9-2√3x - x²)/(3-x²)

= [9-3√3x + √3x - x²]/[(√3)² - x²]

= [3√3(√3-x)+x(√3- x)]/[((√3+x)(√3-x)]

= [(√3 - x) (3√3+x) ]/[(√3+x)(√3-x)]

After cancellation,

= (3√3 + x)/(√3 + x)

Answer 2

Step-by-step explanation:

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