Simplify by making mathematical expressions. The sum of 32 and 18 is divided by 5 and the sum of quotient and 11 is divided by 7.
Answers
Step-by-step explanation:
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Grade 7
Mathematics
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Chapters in NCERT Solutions - Mathematics, Class 7
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Exercises in Simple Equations
Question 4
Q4) Write equations for the following statements:
(i) The sum of numbers x and 4 is 9. (ii) 2 subtracted from y is 8.
(iii) Ten times a is 70. (iv) The number b divided by 5 gives 6.
(v) Three-fourth of t is 15. (vi) Seven times m plus 7 gets you 77.
(vii) One-fourth of a number x minus 4 gives 4.
(viii) If you take away 6 from 6 times y, you get 60.
(ix) If you add 3 to one-third of z, you get 30.
Solution
Transcript
Solution 4:
(i) x+4=9
x=9-4
x= 5
(ii) y-2=8
y=8+2
y=10
(iii) a\times10\ =\ 70a×10 = 70
(iv) \frac{b}{5}=\ 6\
5
b
= 6
b= 30
(v) \frac{3}{4}\times t\ =\ 15\
4
3
×t = 15
t\ =\ 15\times\frac{4}{3}t = 15×
3
4
t = 20
(vi) \frac{b}{5}=\ 6\
5
b
= 6
b\ =\ 6\ \times5\ b = 6 ×5
b = 30
3
Step-by-step explanation:
The sum of 32 and 18 is divided by 5 and sum of quotient and 11 is divided by 7
=> [{(sum of 32 and 18) divided by 5} + 11] ÷ 7
=>[ {(32 + 18) ÷ 5} + 11] ÷ 7
=> [{50 ÷ 5} + 11] ÷ 7
=> [10 + 11] ÷ 7
=> 21 ÷ 7
=> 3
Hence simplification is 3.
hope it helps.