Math, asked by yathi3, 1 year ago

simplify by ratializing the denaminator √3-√5÷√3+√5

Answers

Answered by AjayKumar111111
2

 \frac{ \sqrt{3}  -  \sqrt{5} }{ \sqrt{3} +  \sqrt{5}  }  \times  \frac{ \sqrt{3} -  \sqrt{5}  }{ \sqrt{3}  -  \sqrt{5} }
 \frac{3 + 5 - 2 \sqrt{15} }{3 - 5}  =  \frac{8  - 2 \sqrt{15} }{ - 2}
 \frac{ - 2( \sqrt{15 }  - 4)}{ - 2}  =  \sqrt{15 }  - 4
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Answered by kitty001
2
 \frac{ \sqrt{3} - \sqrt{5} }{ \sqrt{3} + \sqrt{5} } =
(√3-√5)^2/(3-5)=3+5-2√15/-2=2√15-8/2=
 \frac{ \sqrt{15} - 4}{1}

and thus the ans.

kitty001: please mark brainliest...
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