Question

Simplify by rationalising denominator: 6/3√2-2√3​

Answer 1

$\huge\sf\green{Answer}$

$3 \sqrt{2} + 2 \sqrt{3}$

$\huge\sf\pink{ Explanation:}$

$\frac{6}{3 \sqrt{2} - 2 \sqrt{3} }$

$➩ \:\: \frac{6}{3 \sqrt{2} - 2 \sqrt{3} } \times \frac{3 \sqrt{2} + 2 \sqrt{3} }{3 \sqrt{2} + 2 \sqrt{3} }$

$➩ \:\:\frac{6 \: (3 \sqrt{2} + 2 \sqrt{3}) }{(3 \sqrt{2} - 2 \sqrt{3}) \times (3 \sqrt{2} + 2 \sqrt{3} )}$

$➩ \: \:\frac{18 \sqrt{2} + 12 \sqrt{3} }{( {3 \sqrt{2} )}^{2} - ( {2 \sqrt{3} )}^{2} }$

$➩ \: \:\frac{18 \sqrt{2} + 12 \sqrt{3} }{18 \: - 12}$

$➩ \:\:\frac{6 \: (3 \sqrt{2} + 2 \sqrt{3} )}{6}$

$➩ \:\:3 \sqrt{2} + 2 \sqrt{3}$

$\boxed{3√2 + 2√3}$

Answer 2

Hii your answer is 3√2+2√3

Explanation:

refer to the attachment