Question

simplify by rationalising the denominator : (2root6/root2+root3)+(6root2/root6+root3)-(8root3/root6+root2)​

Answer 1

Ans:- 2√6/√2+√3 + 6√2/√6+√3 - 8√3/√6+√2

= 2√6/(√2+√3)×(√2-√3)/(√2-√3) + 6√2/(√6+√3)×(√6-√3)/(√6-√3) - 8√3/(√6+√2)×(√6-√2)/(√6-√2)

= (2√12-2√18)/(2-3) + (6√12-6√6)/(6-3) - (8√18-8√6)/(6-2)

= (4√3-6√2)/-1 + (12√3-6√6)/3 - (24√2-8√6)/4

= -4√3+6√2 + 4√3-2√6 - (6√2-2√6)

= 6√2-4√3 + 4√3-2√6 - 6√2+2√6

= 0.

here is your answer

hope it will help you