Math, asked by AyushmanDas8688, 9 months ago

Simplify by rationalizing the denomenator of 2×root6/3+root3

Answers

Answered by codiepienagoya
0

Simplify:

Step-by-step explanation:

\ Given \ value:\\\\\frac{2\times\sqrt{6}}{3+\sqrt{3}}\\\\\ Solution: \\\\\frac{2\times\sqrt{6}}{3+\sqrt{3}}\\\\\rightarrow \frac{2\sqrt{6}}{3+\sqrt{3}} \times \frac{3-\sqrt{3}}{3-\sqrt{3}} \\\\\rightarrow \frac{2\sqrt{6}(3-\sqrt{3})}{3^2-(\sqrt{3})^2} \\\\\rightarrow \frac{6\sqrt{6}-2\sqrt{6}\sqrt{3}}{3^2-(\sqrt{3})^2} \\\\\rightarrow \frac{6\sqrt{6}-2\sqrt{6}\sqrt{3}}{9-3} \\\\\rightarrow \frac{6\sqrt{6}-6\sqrt{2}}{6} \\\\\rightarrow (\sqrt{6}-\sqrt{2}) \\

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