Question

simplify by rationalizing the denominator 7 + 3 root 5 upon 7 minus 3 root 5​

Answer 1

The answer is provided systematically.

click above for your answer

Answer 2

$\frac{7 + 3 \sqrt{5} }{7 - 3 \sqrt{5} } \\ \\ = \frac{(7 + 3 \sqrt{5}) }{(7 - 3 \sqrt{5}) } \times \frac{( 7 + 3 \sqrt{5} )}{( 7 + 3 \sqrt{5})} \\ \\ = \frac{ {(7 + 3 \sqrt{5}) }^{2} }{ {(7)}^{2} - {(3 \sqrt{5}) }^{2} } \\ \\ = \frac{49 + 42 \sqrt{3} + 45 }{49 - 45} \\ \\ = \frac{94 + 42 \sqrt{3} }{4} = \frac{47 + 21 \sqrt{3} }{2}$