Question

simplify by removing racidal sings and negative indies ✓4^3​

Answer 1

Answer:

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Answer 2

$\huge\underline{\overline{\mid{\bold{\pink{question-}}\mid}}}$

A person travelling on a scooter at 43.2 km/h giving a deceleration of 6m/s² to his scooter. How far will it travel before stopping (v=0)

$</p><p>\huge\underline{\overline{\mid{\bold{\pink{ANSWER-}}\mid}}} </p><p>$

Distance travelled before stopping is 12m

$\Large{\underline{\underline{\bf{Given:-}}}} </p><p>$

Initial velocity = 43.2km/h

Initial velocity = 43.2km/hAcceleration = - 6m/s²

$</p><p>\Large{\underline{\underline{\bf{Find:-}}}} </p><p>$

Distance travelled before stopping ?

Distance travelled before stopping ?Here we go yo ^^":−

$</strong></p><p></p><p><strong>[tex]\Large{\underline{\underline{\bf{SoLuTion:-}}}} </strong></p><p><strong>[tex]\Large{\underline{\underline{\bf{SoLuTion:-}}}}$

❥ Final velocity = 43.2 km/h

❥ Final velocity = 43.2 km/h❥ v = 12 m/s

❥ Final velocity = 43.2 km/h❥ v = 12 m/sApplying Third law of motion

❥ Final velocity = 43.2 km/h❥ v = 12 m/sApplying Third law of motion↠ v² = u² + 2as

❥ Final velocity = 43.2 km/h❥ v = 12 m/sApplying Third law of motion↠ v² = u² + 2as" v " = final velocity

❥ Final velocity = 43.2 km/h❥ v = 12 m/sApplying Third law of motion↠ v² = u² + 2as" v " = final velocity" u " = initial velocity

❥ Final velocity = 43.2 km/h❥ v = 12 m/sApplying Third law of motion↠ v² = u² + 2as" v " = final velocity" u " = initial velocity" a " = acceleration

❥ Final velocity = 43.2 km/h❥ v = 12 m/sApplying Third law of motion↠ v² = u² + 2as" v " = final velocity" u " = initial velocity" a " = acceleration" s " = distance

❥ Final velocity = 43.2 km/h❥ v = 12 m/sApplying Third law of motion↠ v² = u² + 2as" v " = final velocity" u " = initial velocity" a " = acceleration" s " = distance❥ (0)² = (12)² + 2 × (-6) × s

❥ Final velocity = 43.2 km/h❥ v = 12 m/sApplying Third law of motion↠ v² = u² + 2as" v " = final velocity" u " = initial velocity" a " = acceleration" s " = distance❥ (0)² = (12)² + 2 × (-6) × s❥ 0 = 144 - 12s

❥ Final velocity = 43.2 km/h❥ v = 12 m/sApplying Third law of motion↠ v² = u² + 2as" v " = final velocity" u " = initial velocity" a " = acceleration" s " = distance❥ (0)² = (12)² + 2 × (-6) × s❥ 0 = 144 - 12s❥ 12s = 144

❥ Final velocity = 43.2 km/h❥ v = 12 m/sApplying Third law of motion↠ v² = u² + 2as" v " = final velocity" u " = initial velocity" a " = acceleration" s " = distance❥ (0)² = (12)² + 2 × (-6) × s❥ 0 = 144 - 12s❥ 12s = 144❥ s = 144/12

❥ Final velocity = 43.2 km/h❥ v = 12 m/sApplying Third law of motion↠ v² = u² + 2as" v " = final velocity" u " = initial velocity" a " = acceleration" s " = distance❥ (0)² = (12)² + 2 × (-6) × s❥ 0 = 144 - 12s❥ 12s = 144❥ s = 144/12❥ s = 12 m

$\mathfrak{\huge{\purple{\underline{\underline{Hence}}}}} </p><p>$

S = 12m

$</p><p>\Large{\underline{\underline{\bf{Additional Information:-}}}}$

❥ In the first law, an object will not change its motion unless a force acts on it.

❥ In the first law, an object will not change its motion unless a force acts on it.❥ In the second law, the force on an object is equal to its mass times its acceleration.

❥ In the first law, an object will not change its motion unless a force acts on it.❥ In the second law, the force on an object is equal to its mass times its acceleration.❥ In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

❥ In the first law, an object will not change its motion unless a force acts on it.❥ In the second law, the force on an object is equal to its mass times its acceleration.❥ In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.____________________________