Question

simplify cos (360 -A) tan ( 360 +A) / cot (270 - A) sin ( 90 +A )​

Answer 1

Given :

$\frac{\cos (360-A)\tan(360+A)}{\cot (270 - A)\sin (90+A) }$

Explanation :

In the given Sum we can find values by :

(i) Substituting trigonometric ratios

(ii) Cancelling the common terms in fraction

Solution :

$\implies\frac{\cos (360-A)\tan(360+A)}{\cot (270 - A)\sin (90+A) }$

$\implies \frac{\cos A \times \tan A}{\tan A \times \cos A }$

$(\because \cos (360 - \theta = \cos \theta \:\:\&\:\: \tan (360 + \theta)=\tan \theta)$

$(\because \cot (270+\theta)=\tan \theta\:\:\&\:\: \sin(90+\theta)=\cos \theta)$

$\implies \boxed{\bf{}1}$