Question

simplify (Cos power6 teta +sin power6 teta)+3sin square teta.Cos square teta​

Answer 1

Answer:

( sin^{2}θ + cos^{2}θ ) ^ 3

( a +b)^{3} =  a^{3} + b^{3} + 3ab( a+b)

let a  be  sin^{2}θ

let b  be cos^{2}θ

As we know  sin^{2}θ + cos^{2}θ = 1

So,  a + b = 1

(a +b)^3 = sin^6θ +cos^6θ +3sin^2θ . cos^2θ ( a+b)

Substitute a+b as 1.

We get required answer.

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